php ?
php ?
Out of context: Reply #2
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echo this i mean:
echo "[img src=\"img/galleries/2000/2000_01... /]";
but replace "2000" with the var $yr, and the number "1" after the "_0" with the var $i
any help with the trick quotes/ slash syntax would be seroiusly appreciated
i am braindead and need to go home and need to learn php