Quick SQL help
Quick SQL help
Out of context: Reply #5
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- Ginja0
I bought a book so cant give a link sorry.
Error is... mysql_fetch_array(): supplied argument is not a valid MySQL result resource
More code:
while( $row = mysql_fetch_array( $rs ) )
{
echo( "Movie: " . $row["movietitle"] ."");
echo( "Person & Number: " . $row["person"] ." - " . $row["number"] ."");
echo( "Extra Info: " . $row["description"] ."");
}