QBN Ratio

Out of context: Reply #16

  • Started
  • Last post
  • 62 Responses
  • MrDinky0

    FRatioDistribution["n", "m"]

    mean | m/(m-2) for m>2
    standard deviation | (sqrt(2) m sqrt(m+n-2))/(sqrt(m-4) (m-2) sqrt(n)) for m>4
    variance | (2 m^2 (m+n-2))/((m-4) (m-2)^2 n) for m>4
    skewness | (2 sqrt(2) sqrt(m-4) (m+2 n-2))/((m-6) sqrt(n) sqrt(m+n-2)) for m>6
    kurtosis | (12 ((m-4) (m-2)^2+(5 m-22) n (m+n-2)))/((m-8) (m-6) n (m+n-2))+3 for m>8

    ean | m/(m-2) for m>2
    standard deviation | (sqrt(2) m sqrt(m+n-2))/(sqrt(m-4) (m-2) sqrt(n)) for m>4
    variance | (2 m^2 (m+n-2))/((m-4) (m-2)^2 n) for m>4
    skewness | (2 sqrt(2) sqrt(m-4) (m+2 n-2))/((m-6) sqrt(n) sqrt(m+n-2)) for m>6
    kurtosis | (12 ((m-4) (m-2)^2+(5 m-22) n (m+n-2)))/((m-8) (m-6) n (m+n-2))+3 for m>8

    (m^(m/2) n^(n/2) x^(-1 + n/2) (m + n x)^((-m - n)/2))/Beta[n/2, m/2]
    with/or
    PDF[FRatioDistribution[n, m], x]

    {FRatioDistribution[2, 3], FRatioDistribution[3, 2]}

    BetaRegularized[(n x)/(m + n x), n/2, m/2] / CDF[FRatioDistribution[n, m], x] / I_((n x)/(m+n x))(n/2,m/2)

    {FRatioDistribution[2, 3], FRatioDistribution[3, 2]}

    MrDinky 0Permalink
    UpvoteDownvote
    Flag
    • you left out the box of kleenex for all the internet tearsPonyBoy
    Show [[ numHiddenNotes ]] more notesAdd Note
    SaveCancel

View thread