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Out of context: Reply #12
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- MrDinky0
SOLVE THIS
FRatioDistribution["n", "m"]
mean | m/(m-2) for m>2
standard deviation | (sqrt(2) m sqrt(m+n-2))/(sqrt(m-4) (m-2) sqrt(n)) for m>4
variance | (2 m^2 (m+n-2))/((m-4) (m-2)^2 n) for m>4
skewness | (2 sqrt(2) sqrt(m-4) (m+2 n-2))/((m-6) sqrt(n) sqrt(m+n-2)) for m>6
kurtosis | (12 ((m-4) (m-2)^2+(5 m-22) n (m+n-2)))/((m-8) (m-6) n (m+n-2))+3 for m>8
ean | m/(m-2) for m>2
standard deviation | (sqrt(2) m sqrt(m+n-2))/(sqrt(m-4) (m-2) sqrt(n)) for m>4
variance | (2 m^2 (m+n-2))/((m-4) (m-2)^2 n) for m>4
skewness | (2 sqrt(2) sqrt(m-4) (m+2 n-2))/((m-6) sqrt(n) sqrt(m+n-2)) for m>6
kurtosis | (12 ((m-4) (m-2)^2+(5 m-22) n (m+n-2)))/((m-8) (m-6) n (m+n-2))+3 for m>8
(m^(m/2) n^(n/2) x^(-1 + n/2) (m + n x)^((-m - n)/2))/Beta[n/2, m/2]
with/or
PDF[FRatioDistribution[n, m], x]
{FRatioDistribution[2, 3], FRatioDistribution[3, 2]}
BetaRegularized[(n x)/(m + n x), n/2, m/2] / CDF[FRatioDistribution[n, m], x] / I_((n x)/(m+n x))(n/2,m/2)
{FRatioDistribution[2, 3], FRatioDistribution[3, 2]}